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 A body is released from a great height and falls freely towards the earth. Another body is released from the same height exactly one second later. The separation between the two bodies, two seconds after the release of the second body is  -
 

Option: 1

10 m


Option: 2

22.5 m


Option: 3

26.5 m

 


Option: 4

24.5 m


Answers (1)

best_answer

 

Motion of Body Under Gravity (Free Fall) -

The force of attraction of earth on any body is called force of gravity. Acceleration produced on the body by the force of gravity, is called acceleration due to gravity. It is represented by the symbol ‘g’.

There are three cases basically in this - 

             1) If a body dropped from some height (initial velocity zero)

                      u = 0 

                      a = g

                     \begin{array}{l}{v=g t} \\ {h=\frac{1}{2} g t^{2}} \\ {v^{2}=2 g h} \\ {h_{n}=\frac{g}{2}(2 n-1)}\end{array}  

The sepration between two bodies, two second after the release of second body is given by

\\s=\frac{1}{2}.g.\left ( t_{1}^{2}-t_{2}^{2} \right )\\* \frac{1}{2}\times 9.8\times \left ( 3^{2}-2^{2} \right )= 24.5m

Posted by

vishal kumar

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