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  • A body of mass 1 Kg is attached to one end of a wire and rotated in a horizontal circle of diameter 40 cm with a constant speed of 2 m/s. What is the area (in mm2) of cross-section of th

A body of mass 1 Kg is attached to one end of a wire and rotated in a horizontal circle of diameter 40 cm with a constant speed of 2 m/s. What is the area (in mm2) of cross-section of the wire if the stress developed in the wire is 5 \times 10 ^6 N / m^2 ?

Option: 1

2


Option: 2

3


Option: 3

4


Option: 4

5


Answers (1)

best_answer

As we have learned

Stress -

The internal restoring force acting per unit area of the cross-section of the deformed body is called stress.

 

 Tension in the wire = \frac{mv^2 }{r}= \frac{1 \times (2)^2}{0.2}= 20 N

 

Stress = F/A

SO  A = F / stress = \frac{20 }{5 \times 10 ^6 }

A = 4 \times 10 ^{-6} m^2 = 4 mm^2

 

 

 

 

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