Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A canon shell moving along a straight line bursts into two parts. Just after the burst one part moves with momentum 20 Ns making an angle 30º with the original line of motion. The minimum mome

A canon shell moving along a straight line bursts into two parts. Just after the burst one part moves with momentum 20 Ns making an angle 30º with the original line of motion. The minimum momentum (in N-s) of the other part of shell just after the burst is :

Option: 1

0


Option: 2

5


Option: 3

10


Option: 4

17.32


Answers (1)

best_answer

                        

Given :P_{1} = 20 Ns
Let the minimum momentum of the other parts be P_{2}


Applying conservation of momentum in y direction:

                                \begin{array}{l}{P_{1} \sin 30=P_{2} \sin \theta} \\ \\ {20 \times \frac{1}{2}=P_{2} \sin \theta}\end{array}

                              P_{2} \sin \theta=10 \ \mathrm{Ns}

For P2 to be maximum, Sin \theta should be maximum. Maximum  Sin \theta = 1

                                          P2 = 10 N-s

Posted by

Anam Khan

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

Telangana to offer free JEE, NEET, CLAT coaching to government school students
anam-khan

BTech 2025 Admission LIVE: JoSAA revised schedule out on josaa.nic.in; updates on MHT CET, KEAM counselling
anam-khan

Andhra launches free JEE, NEET coaching to over 1 lakh govt school students

Latest Question