Get Answers to all your Questions

header-bg qa

A cell of emf E is connected across resistance R.The potential difference between the terminal of a cell is found to be V.The internal resistance of the cell must be

Option: 1

\frac{E-V}{V}.R


Option: 2

(E-V).R


Option: 3

2\frac{E-V}{E}.R


Option: 4

2\frac{E-V}{R}.V


Answers (1)

best_answer

As we learnt

 

Internal resistance -

 

In case of a cell the opposition of electrolyte to the flow of current through it 

- wherein

It is showed by r

 

 

V=E-Ir 

I=\frac{E}{r+R}

V=E-\frac{E}{r+R}.r=E.\frac{R}{r+R}

or\: \: \frac{r}{R}+1= \frac{E}{V}\: \: or\: \: r=\left ( \frac{E}{V}-1 \right )R

Posted by

qnaprep

View full answer