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  • A chord of the circle lies along the line <img alt="\mat

A chord of the circle \mathrm{(x-1)^2+y^2=16} lies along the line \mathrm{y=22 \sqrt{3}(x-1)}. The length of the chord is
 

Option: 1

\mathrm{4\: \: units}


 


Option: 2

\mathrm{4 \sqrt{3} \: units}


Option: 3

\mathrm{8 \: units}
 


Option: 4

None of these
 


Answers (1)

best_answer

The given line passes through the centre (1,0) of the circle. Hence it is a diameter.

\mathrm{\Rightarrow } Its length \mathrm{=2 } (radius)\mathrm{=8\: units. }

Hence option 3 is correct.

Posted by

Irshad Anwar

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