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  • A circular loop of radius 0.3 cm lies parallel to a much bigger circular loop of radius 20 cm. The centre of the small loop is on the axis of the bigger loop. The distance between their centre

A circular loop of radius 0.3 cm lies parallel to a much bigger circular loop of radius 20 cm. The centre of the small loop is on the axis of the bigger loop. The distance between their centres is 15 cm. If a current of 2.0 A flows through the smaller loop, then the flux linked with bigger loop is:

 

Option: 1

6.6\times10-9 weber


Option: 2

9.1\times10-11 weber


Option: 3

6\times10-11 weber


Option: 4

3.3\times10-11 weber


Answers (1)

best_answer

 

M_{12}=M_{21}

Here we will calculate flux through smaller loop due to bigger loop 

  B_{21 } = \frac{\mu _0I_1r_{1}^{2}}{2(r_{1}^{2}+x^2)^{3/2}}

Q_{21} = B_{21 } A_2 = B_2 \times \pi r_{2}^{2} =\frac{\mu _0 \pi r_{1}^{2}r_{2}^{2}}{2(x^{2}+ r _{1}^{2})^{3/2}}\cdot I_1

But \phi _{21} = M_{21}I_1

\frac{\mu _0 \pi r_{1}^{2}r_{2}^{2}}{2(x^{2}+ r _{1}^{2})^{3/2}} = M_{12}

\phi _{12 } = M_{12} I_2 = 4. 55 \times 10^{-11}\times 2 = 9.1 \times 10^{-11}Wb

Posted by

Ritika Harsh

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