Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A coil having N turns is wound tightly in the form of a spiral with inner & outer radii, a & b respectively. When a current I passes throuhg the coil, the magnetic field at the centre will

A coil having N turns is wound tightly in the form of a spiral with inner & outer radii, a & b respectively. When a current I passes throuhg the coil, the magnetic field at the centre will be

Option: 1

\frac{\mu oNI}{b}


Option: 2

\frac{\mu oNI}{a}


Option: 3

0


Option: 4

\frac{\mu oIN}{2\left ( b-a \right )}ln\frac{b}{a}


Answers (1)

best_answer

Number of turns per unit width = \frac{N}{b-a}

considering ring of radius x, thickness 'dx'
 number of turns in ring dN = \frac{Ndx}{b-a},
\int dB=\frac{\mu_o(dN)i}{2x}=\frac{\mu_oi}{2}\int_{a}^{b}\frac{Ndx}{b-a}\cdot \frac{1}{x}\Rightarrow \frac{\mu_oiN}{2\left ( b-a \right )}ln\frac{b}{a}
Posted by

manish painkra

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

Andhra launches free JEE, NEET coaching to over 1 lakh govt school students
anam-khan

JoSAA Counselling 2025 LIVE: BTech registration starts at josaa.nic.in for IIT, NIT, IIIT admissions
anam-khan

Kota: 17-year old student from UP preparing for JEE dies of electrocution in hostel

Latest Question