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A convex lens of focal length  f is placed somewhere in between an object and a screen. The distance between the object and the screen is x. If the numerical value of the magnification produced by the lens is  m , then the focal length of the lens is

Option: 1

\frac{m x}{(m+1)^{2}}


Option: 2

\frac{m x}{(m-1)^{2}}


Option: 3

\frac{(m+1)^{2}}{m} x


Option: 4

\frac{(m-1)^{2}}{m} x


Answers (1)

best_answer

\frac{v}{u}=m

\text { and } v+u=x

\Rightarrow u=\frac{x}{1+m}

\frac{1}{f}=\frac{1}{v}-\frac{1}{u}

\Rightarrow f=\frac{m x}{(m+1)^{2}}

Posted by

Riya

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