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A current of 10A is flowing in a wire of length 1.5m. A force of 15N acts on it when it is placed in a uniform magnetic field of 2T. The angle between the magnetic field and the direction of the current is

Option: 1

30^{\circ}


Option: 2

45^{\circ}


Option: 3

60^{\circ}


Option: 4

90^{\circ}


Answers (1)

best_answer

As we learnt

 

Magnetic force for a straight conductor -

 

F=Bil\sin \theta

-

 

 \sin \theta = \frac{F}{ilB}

            =\frac{15}{10*1.5*2}= \frac{1}{2}

        \theta =30^{\circ}

 

Posted by

SANGALDEEP SINGH

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