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A dry cell delivering 2A has terminal voltage 1.41V.What is the internal resistance (in \Omega)  of the cell if its open circuit voltage is 1.59V?

Option: 1

0.09


Option: 2

6.09


Option: 3

7.09


Option: 4

5.09


Answers (1)

best_answer

As we learnt

Potential drop inside the cell -

ir

-

Open circuit voltage E=1.59V

P.D. across internal resistance is Ir.

\therefore V=E-Ir\: \: or\: \: 1.41=1.59-2r

or\: \: r=0.09\Omega

Posted by

SANGALDEEP SINGH

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