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A jet plane is travelling west at the speed of\mathrm{1600\; kmh^{-1}}. The voltage difference developed between the ends of the wing having a span of 20 m, if the earth’s magnetic field at the location has a magnitude of \mathrm{5 \times 10^{-4} \mathrm{~T}} and the dip angle is 30° is:

Option: 1

4.1 V


Option: 2

2.2 V


Option: 3

3.2 V


Option: 4

3.8 V


Answers (1)

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\mathrm{Here, \mathrm{v}=1600 \mathrm{kmh}^{-1}=1600 \times \frac{5}{18} \mathrm{~ms}^{-1}=444 \mathrm{~ms}^{-1} }

\mathrm{l=20 \mathrm{~m}, \mathrm{~B}=5 \times 10^{-4} \mathrm{~T}\; and\; \delta=30^{\circ}}

\mathrm{\text { As } \varepsilon=\mathrm{B} l \mathrm{v}=\mathrm{Vlv}} (where V is the vertical component of earth’s field)

\mathrm{\begin{aligned} & =(B \sin 8) l v \quad(\because V=\sin 8) \\ & =5 \times 10^{-4} \sin 30^{\circ} \times 20 \times 444=2.2 \mathrm{~V} \end{aligned}}

 

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Ritika Kankaria

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