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  • A machine gun fires a bullet of mass 40g with a velocity 1200 ms-1 The man holding it can exert a maximum force of 144 N on the

Screenshot_13.png New Tab dt MyWay Newton's 2nd Law —JEE Main Sti X htt m =jee-m ai uestio ns kdp d(mv) Therefore F K = lin Sl Force can be defined as rate of change of momentum. Videos Question Exam Questions Books Asked in: 81TSAT-2018 A machine gun fires a bullet of mass 40g with a velocity 1200 ms-l The man holding it can exert a maximum force of 144 N on the gum How many bullets can he fire per second at the most ? X Your option is incorrect c. O O O one four two three « Previous Concept List Next » 2/19/2019

Answers (1)

@Tanvi

Suppose he can fire n bullets per second

Force = Change in momentum per second

144= n\times \left ( \frac{40}{1000} \right )\times \left ( 1200 \right )

or\: \:\: \: n= \frac{144\times 1000}{40\times 1200}

or\: \:\: \: n= 3

40 1000 x (1200) 40 x 1200
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