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  • A massless rope is fixed at one end as shown in fig. Two boys of masses 40kg and 60kg are moving along the rope. The former climbing up with an acceleration of <img alt="2m/s^2" src="http://en

A massless rope is fixed at one end as shown in fig. Two boys of masses 40kg and 60kg are moving along the rope. The former climbing up with an acceleration of 2m/s^2 while later coming down with a constant velocity of   5m/s. The tension (in N) at fixed support will be (g=10m/s^2)

Option: 1

1080


Option: 2

1000


Option: 3

1200


Option: 4

1100


Answers (1)

best_answer

Solution :

  \\ \text{For 40 Kg block :}

\\ \text{As 40KG Boy is accelerating upwards }

T-T_1-40g=40a

T=T_1+40g+40\times 2

\\ T=T_1+40g+40\times 2 \\ T=T_{1}+400+80 \\ T=T_{1}+480 \ \ \ \ -(1)

\\ \text{For 60 Kg block :}

\\ \text{As 60Kg boy is in uniform velocity, So acceleration of 60 kg will be zero }

\therefore T_{1}= 60g = 60\times 10 = 600 N \text {put in equation (1) }

\\ T= 600+480= 1080 N

 

Posted by

manish painkra

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