Get Answers to all your Questions

header-bg qa

A metal rod of length 2 m is rotating with an angular velocity of \mathrm{100 \; rad \; s^{-1}} in a plane perpendicular to a uniform magnetic field of 0.3 T. The potential difference between the ends of the rod is:

Option: 1

30 V


Option: 2

40 V


Option: 3

60 V


Option: 4

600 V


Answers (1)

best_answer

\mathrm{\text { Here, } l=2 \mathrm{~m}, \omega=100 \mathrm{rads}^{-1}, \mathrm{~B}=0.3 \mathrm{~T}}

The potential difference between the ends of rod is

\mathrm{\varepsilon=\frac{1}{2} \mathrm{~B} \omega l^2=\frac{1}{2} \times 0.3 \times 100 \times(2)^2=60 \mathrm{~V}}

Posted by

Suraj Bhandari

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE