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A monkey moves 6m north, 8m east and 10m vertically upward on a pole. What will be the displacement from the initial reference point?

Option: 1

10\sqrt{2}m


Option: 2

10\: m


Option: 3

5 \: m


Option: 4

\frac{10}{\sqrt{2}}m


Answers (1)

best_answer

 

       

the motion of the monkey is as follows

A monkey moves 6m north (i.e 6m along +y axis),

8m east (i.e  8 m along +x axis) and 10m  vertically upward on a pole (i.e  10m along +z axis)

\text{Displacement of monkey} \ (\vec{s})=8\hat{i}+ 6\hat{j}+10\hat{k}

\text{Magnitude of displacement}\left (|\vec{s} \right |)= \sqrt{8^{2}+6^{2}+10^{2}}=10\sqrt{2}m

Posted by

jitender.kumar

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