Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A nucleus of in an excited state decays to its ground state by emitting a <img alt="1.33 \mathrm{MeV}

A nucleus of { }^{60} \mathrm{Ni} in an excited state decays to its ground state by emitting a 1.33 \mathrm{MeV} photon. The recoil speed of the { }^{60} \mathrm{Ni} nucleus is:
 

Option: 1

7.07 \times 10^3 \mathrm{~m} / \mathrm{s}


Option: 2

5.07 \times 10^3 \mathrm{~m} / \mathrm{s}


Option: 3

7.07 \times 10^4 \mathrm{~m} / \mathrm{s}


Option: 4

7.07 \times 10^5 \mathrm{~m} / \mathrm{s}


Answers (1)

best_answer

Momentum of the photon, \begin{aligned} & \mathrm{p}=\frac{E}{c}=\frac{\left(1.33 \times 10^6\right)\left(1.6 \times 10^{-19}\right)}{3 \times 10^8} \\ & =7.09 \times 10^{-22} \mathrm{kgms}^{-1} \\ \end{aligned}

Using momentum conservation recoil energy of the

\begin{aligned} &{ }^{60} \mathrm{Ni} \text{ is } \mathrm{E} = \frac{p^2}{2 m}=\frac{\left(7.09 \times 10^{-22}\right)^2}{2\left(60 \times 1.67 \times 10^{-27}\right)} & =2.51 \times 10^{-18} \mathrm{~J}=1.57 \times 10^{-5} \mathrm{MeV} \end{aligned}

Recoil speed of the nucleus, v=\frac{p}{\mathrm{~m}}=\frac{7.09 \times 10^{-22}}{60 \times 1.67 \times 10^{-27}}=7.07 \times 10^3 \mathrm{~m} / \mathrm{s}

Posted by

Sayak

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026 Registration LIVE: NTA session 1 form link at jeemain.nta.nic.in; application deadline
anam-khan

JEE 2026: IIT admissions show major shift toward AI, data science, away from core engineering courses
anam-khan

JEE Main 2026: NIT Delhi cut-offs for BTech courses show ever-increasing demands for AI, computer skills

Latest Question