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  • A particle is moving with its position as function of time is given as S = 4t2 +7t +10 m

A particle is moving with its position as function of time is given as S = 4t2 +7t +10 m then its acceleration is:

Option: 1

Variable
 


Option: 2

Constant and its equal to 8 m/s2


Option: 3

Constant and equal to zero

 


Option: 4

None of the above


Answers (1)

 

\text{Given}:

S= 4t^{2}+7t+10

\\*V=\frac{ds}{dt}=\frac{d}{dt}(4t^{2}+7t+10)\\*\\*V=8t+7\\\\*a=\frac{dV}{dt}=\frac{d}{dt}\left ( 8t+7 \right )\\\\=8\, m/s^{2}

 

Posted by

Kshitij

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