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  • A particle is projected with initial speed 30 m/s at an angle of 30o with horizontal then maximum height (in meter) attained by the particle is (g = 10 m/s2) &nbsp

A particle is projected with initial speed 30 m/s at an angle of 30o with horizontal then maximum height (in meter) attained by the particle is (g = 10 m/s2)
 

Option: 1

10.25


Option: 2

11.25


Option: 3

22.5


Option: 4

13.25


Answers (1)

best_answer

\begin{aligned} &\text { Here } \mathbf{u}=\mathbf{3 0} \mathbf{m s}^{-1} \text {, Angle of projection, } \boldsymbol{\theta}=\mathbf{3 0^o}\\ &\text { Maximum height, }\\ &H=\frac{u^{2} \sin ^{2} \theta}{2 g}=\frac{30^{2} \sin ^{2} 30^{\circ}}{2 \times 10}=\frac{900}{20} \times \frac{1}{4}=\frac{45}{4} \mathrm{~m} \end{aligned}

So,

H = 11.25 m

 

Posted by

Ritika Harsh

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