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  • A particle of mass m moving in the x direction with speed is hit by another particle

A particle of mass m moving in the x direction with speed 2 \upsilon is hit by another particle of mass 2m moving in the y direction with speed \upsilon. If the collision is perfectly inelastic, the percentage loss in the energy during the collision is close to :

Option: 1

44%


Option: 2

50%


Option: 3

56%


Option: 4

62%


Answers (1)

best_answer

As learnt in

E_{1}=\frac{1}{2}m(2v)^{2}+\frac{1}{2}2mv^{2}

E_{1}=3mv^{2}

Now, the mass becomes (2m+m)=3m

3mv= \sqrt{(2mv)^{2}+(2mv)^{2}}

v=\frac{2 \sqrt2 v}{3}

E_{2}=\frac{1}{2}3m \left ( \frac{2 \sqrt 2v}{3} \right )^{2}

E_{2}=\frac{4}{3}v^{2}

\frac{E_{1}-E_{2}}{E_{1}}= \frac{5}{\frac{3}{3}}\times 100

\% \:\:change= \frac{5}{9}\times 100=56\%

 

 

Posted by

mansi

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