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  • A person lives in a high- rise building on the bank of a river 50 m wide. Across the river is a well lit tower of height 40 m. When the person, who is at a height of 10 m, looks through a polarizer

A person lives in a high- rise building on the bank of a river 50 m wide. Across the river is a well lit tower of height 40 m. When the person, who is at a height of 10 m, looks through a polarizer at an appropriate angle at light of the tower reflecting from the river surface, he notes that intensity of light coming  from distance X from his building is the least and this corresponds to the light coming from light bulbs at height 'Y' on the tower. The values of X and Y are respectively close to (refractive inde of water \simeq 4/3)

Option: 1

25 m, 10 m 


Option: 2

13 m, 27 m 


Option: 3

22 m, 13 m 


Option: 4

17 m, 20 m 


Answers (1)



\\ i= Brewster's \ angle \\ \\ =\tan ^{-1}(\mu) \\ =\tan ^{-1}\left(\frac{4}{3}\right) \\ i=53^{\circ} \\ \therefore \tan 37^{\circ}=10 / X \\ \\ \frac{3}{4}=\frac{10}{X} \Rightarrow \frac{40}{3}=13.3 m


\begin{aligned} &\text { Again, } \tan 37^{\circ}=\frac{Y}{50-X}\\ &\frac{3}{4}=\frac{Y}{50-X}\\ &\Rightarrow 3\left(50-\frac{40}{3}\right)=4 Y\\ &\Rightarrow 110=4 Y\\ &\therefore Y=27.5 m \end{aligned}
 

Posted by

Ramraj Saini

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