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  • a rope is wound around a cylinder of mass 3kg and radius 30cm angular accelartion when rope is pulled with a force of 30N

neet 2017

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mass of cylinder = 3Kg

radius of cylinder =30cm =.30m

moment of inertia of cylinder  I=mr^2

                                                  = 3*.03*.03

                                                 =.27kgm^2

torque = force * radius

I*\alpha =30*3

\alpha =\frac{100}{3} rad/sec^2

Posted by

neetan kumar lalotra

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