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  • A satellite is launched into a circular orbit of radius R around the earth

 A satellite is launched into a circular orbit of radius R around the earth. A second satellite is launched into an orbit of radius (1.01)R. The period of the second satellite is larger than that of the first one by approximately   

A)           0.5%   

B)             1.0%

C)             1.5%   

D)             3.0%

Answers (1)

best_answer

according to Kepler's third law T^2 isproportional to R^3.

Thus T_{1}=kR^{\frac{3}{2}},T_{2}=kR^{\frac{3}{2}}(1+0.01)^\frac{3}{2}\Rightarrow T_{2}=kR^{\frac{3}{2}}(1+(0.01)*(1.5))

Thus the time period of the second satellite is longer than that of the first one by approximately 1.5%.

Posted by

avinash.dongre

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