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A surface experience a force of 20N over an area of 1cmThen presseure (N/m2) experiences by it is 

Option: 1 20000

Option: 2 200000

Option: 3 2000000

Option: 4 2000

Answers (1)

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As we learned 

 

Pressure -

Normal force exerted by liquid at rest per unit Area of the surface

- wherein

If F be the normal force acting on a surface area A in container with liquid.

 

 P=\frac{F_{n}}{A}=\frac{20N}{10^{-4}m^{2}}= 2\times 10^{5}N/m^{2}

 

Posted by

SANGALDEEP SINGH

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