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  • A Zener diode is connected to a battery and a load as shown below : The currents I, IZ and IL are respectively <img src="https://cdn.entrance360.com/media/

A Zener diode is connected to a battery and a load as shown below :

The currents I, IZ and IL are respectively

Option: 1

5 mA, 5 mA, 10 mA


Option: 2

15 mA, 7.5 mA, 7.5 mA


Option: 3

12.5 mA, 5 mA, 7.5 mA


Option: 4

12.5 mA, 7.5 mA, 5 mA


Answers (1)

best_answer

In the given figure 

Voltage across RL= 2K\Omega is same as that across zener dioxide i.e 10V

\therefore I_{L}= \frac{V_{Z}}{R_{L}}= \frac{10V}{2X10^{3}}=5 m A

Total applied potential = 60 V

\therefore Potential difference across 4K\Omega will be 50 V

Current through 4K\Omega = \frac{50V}{4 \times 10^{3} \Omega}

I= 12.5 m A

\therefore Current through diode

I_{Z}=I - I_{L}= 12.5 mA - 5 mA = 7.5 mA

Posted by

jitender.kumar

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