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  • Among LiCl, BeCl2, BCl3 and CCl4 the covalent bond character varies as :Option: 1 <img alt="\mathrm{LiCll

Among LiCl, BeCl2, BCl3 and CCl4 the covalent bond character varies as :

Option: 1

\mathrm{LiCl< BeCl_{2}< BCl_{3}< CCl_{4}}


Option: 2

\mathrm{LiCl> BeCl_{2}< BCl_{3}< CCl_{4}}


Option: 3

LiCl < BCl3 < BeCl2 <CCl4


Option: 4

\mathrm{LiCl < BeCl_{2}< BCl_{3}> CCl_{4}}


Answers (1)

best_answer

Along the period, electronegativity (EN) increases and hence as we move from Li → Be → B → C, the electronegativity increases and hence the EN difference between the element and Cl decreases and accordingly the covalent character increases.

Thus LiCl < BeCl2 < BCl3 < CCl4 is correct.

Posted by

jitender.kumar

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