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Among the fluorides of alkali metals, the lowest solubility of LiF in H_2 O is due to :

Option: 1

Ionic nature of LiF 


Option: 2

High lattice enthalphy 


Option: 3

High hydration enthalphy for lithium ion 


Option: 4

Low ionisation enthalphy of Li 


Answers (1)

As we have learned 

Due to the small size of Li^+ \: \: and \: \: F^-  ions , lattice enthalpy is much higher than hydration enthalpy and hence LiF is least soluble among alkali metal fluorides.

Hence, the option number (2) is correct.

Posted by

Ramraj Saini

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