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An ammeter reads upto 1amp. Internal resistance of  ammeter is 0.81\Omega. To increase the range to 10A, the value of required shunt (in \Omega ) is

Option: 1

0.09


Option: 2

0.9


Option: 3

0.3


Option: 4

0.03


Answers (1)

best_answer

As we learnt

 

If i_{g} = i/n -

 

s= \frac{G}{(n-1)}

- wherein

To pass n^{th} part of main current through galvanometer

 

 

I_g=I.\left ( \frac{S}{S+Rg} \right )\: \: or\: \: 1+\frac{R_g}{S}= \frac{I}{I_g}= 10

or\: \: \frac{R_g}{S}=9\: \: or\: \: S=\frac{R_g}{9}=0.09\Omega

 

Posted by

SANGALDEEP SINGH

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