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  • An aqueous solution of NaCl is marked 10% (w/w). If the density of the solution is 1.071 gmL-1, what is the molality?

An aqueous solution of NaCl is marked 10% (w/w). If the density of the solution is 1.071 gmL-1, what is the molality?

Answers (1)

best_answer

As we know that 
Molality = No. of moles of the solute/ mass of solvent (in kg)

say, total wt. of solution = 100g

wt of solute (NaCl) = 10 g

So wt of solvent = 90g

no of moles(n) = (given mass)/ Molar mass = 10/58.5 = 0.17094

Molality = \frac{10\times 1000}{58.5\times 90} = 1.90m

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manish

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