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  • An electron makes a transition from orbit n = 4 to the orbit n = 2 of a hydrogen atom. The wave number of the emitted radiations (R = Rydberg's constant) will be<str

An electron makes a transition from orbit n = 4 to the orbit n = 2 of a hydrogen atom. The wave number of the emitted radiations (R = Rydberg's constant) will be

Option: 1

\mathrm{\frac{16}{3R}}


Option: 2

\mathrm{\frac{2R}{16}}


Option: 3

\mathrm{\frac{3R}{16}}


Option: 4

\mathrm{\frac{4R}{16}}


Answers (1)

best_answer

\mathrm{\text { Wave number } \frac{1}{\lambda}=R\left[\frac{1}{n_1^2}-\frac{1}{n_2^2}\right]=R\left[\frac{1}{4}-\frac{1}{16}\right]=\frac{3 R}{16}}

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Ritika Jonwal

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