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  • An electron of mass me and a proton of mass mp are accelerated through same potential difference. The ratio of the de Broglie wavelength associated with an electron

An electron of mass me and a proton of mass mp are accelerated through same potential difference. The ratio of the de Broglie wavelength associated with an electron to that associated with proton is 

Option: 1

1

 

 

 


Option: 2

\frac{m_p}{m_e}


Option: 3

\frac{m_e}{m_p}


Option: 4

\sqrt{\frac{m_p}{m_e}}


Answers (1)

best_answer

As we learned

 

De - Broglie wavelength -

\lambda \: \alpha\; \frac{1}{m}

- wherein

Wave length associated with a heavier particle is smaller than that with a lighter particle.

 

If q the charge on the particle & V is the potential difference a through which it is accelerated then  q\nu =\frac{1}{2}mv^{2}

\Rightarrow mv=\sqrt{2mq\nu }

\therefore \lambda =\frac{h}{mv}=\frac{h}{\sqrt{2mq\nu }}

\frac{\lambda e}{\lambda p}=\sqrt{\frac{m_p}{m_e}}

 

 

Posted by

Suraj Bhandari

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