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An EM wave from air enters a medium.The electric fields are

$\vec{E_{1}}= E_{01} \hat{x} cos [ 2\pi v\left ( \frac{z}{c} \ -t )\right ]$ in air and $\vec{E_{2}}= E_{02} \hat{x} cos [ k (2z-ct) ]$ in medium, where the wave number k and frequency ν refer to their values in air. The medium is non-magnetic. If _andrefer to relative permittivities of air and medium respectively, which of the following options is correct ?

Answers (1)

best_answer

@santosh

Wave equation is given by

$E= E_{o} Sin w (t -\frac{x}{c})$

$E_x=E \sin\left ( \omega t-kx \right )$

$K = \frac{\omega }{C}$

Speed of light formula in vacuum -

$c=\frac{1}{\sqrt{\mu_{o}\epsilon _{o}}}$

c=2.99793 X $10^{8}$ m/s

- wherein

c = Speed of light in vacuum

$\mu_{o}$ = Permeability of vacuum

$\epsilon _{o}$ = Permittivity of vacuum

Speed of light formula in medium-

$c=\frac{1}{\sqrt{\mu_{o}\mu_{r}\epsilon _{o}\epsilon _{r}}}$

$\frac{V}{C}=\frac{1}{2}$ (where v= speed in medium and c=speed of light in air)

For non magnetic medium; $\mu =1$

${\frac{\epsilon _{r1}}{\epsilon_{r2}}} =\frac{1}{4}$

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avinash.dongre

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