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Question

Two point masses 4m and 9m are separeted with distance r. What is the position at which gravitational feild intensity is zero along the line of joining between them.

Your Option is correct !!

A.

\frac{3}{5}r from the mass 4m 

B.

\frac{2}{3}r from the mass 4m

C.

\frac{3}{5}r from the mass 9 m

D.

\frac{2}{3}rfrom the mass 9 m 

Answers (1)

best_answer

Both of these particle are applying a field toward themselves and it would be zero somewhere between them where the field are equal and opposite.

So Let the distance of point where field is zero is x from 4m implies that it would be at distance (r-x) from 9m.

As we know

Gravitational field strength ar distance r = g(r) 

g(r)=\frac{Gm_{p}}{r^{2}}

G - Gravitational Constant 

m_{p} - mass of the particle 

r - distance from the particle

Field by 4m = Field by 9m, so that they cancel out each other. 

\frac{G(4m)}{x^{2}} = \frac{G(9m)}{(r-x)^{2}}

\frac{(r-x)^{2}}{x^{2}} = \frac{9}{4}

\frac{(r-x)}{x} = \frac{3}{2}

x=2r/5

distance from 4m = 2r/5

distance from 9m = 3r/5 

Posted by

Vishwash Tetarwal

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