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  • Answer please! Consider two points 1 and 2 in a region on surface of a charged sphere..1 is inside 2 is on surface If E and V represent the electric field vector and the electric potential, which of the following is possible

Consider two points 1 and 2 in a region on surface of a charged sphere..1 is inside 2 is on surface  If E and V represent the electric field vector and the electric potential, which of the following is  possible

  • Option 1)

    |\bar{E_{1}}|=|\bar{E_{2}}|,V_{1}=V_{2}

     

     

     

     

     

  • Option 2)

    \bar{E_{1}}\neq \bar{E_{2}},V_{1}\neq V_{2}

  • Option 3)

    \bar{E_{1}}\neq \bar{E_{2}},V_{1}=V_{2}

  • Option 4)

    |\bar{E_{1}}|=|\bar{E_{2}}|,V_{1}\neq V_{2}

 

Answers (1)

best_answer

As we learned

 

At the surface of Sphere -

V=R

E_{s}=\frac{1}{4\pi \epsilon _{0}}\frac{Q}{R^{2}}=\frac{\sigma }{\epsilon _{0}}

V_{s}=\frac{1}{4\pi \epsilon _{0}}\frac{Q}{R}=\frac{\sigma R}{\epsilon _{0}}

-

 

 inside sphere E is 0,but V is constant.


Option 1)

|\bar{E_{1}}|=|\bar{E_{2}}|,V_{1}=V_{2}

 

 

 

 

 

Option 2)

\bar{E_{1}}\neq \bar{E_{2}},V_{1}\neq V_{2}

Option 3)

\bar{E_{1}}\neq \bar{E_{2}},V_{1}=V_{2}

Option 4)

|\bar{E_{1}}|=|\bar{E_{2}}|,V_{1}\neq V_{2}

Posted by

Avinash

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