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  • Answer please! In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of someother wavelength. If wavelength of red light is 6600 Å , then wavelength of first maximum will be :

 In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some   
other wavelength. If wavelength of red light is 6600 Å , then wavelength of first maximum will be :  

 

  • Option 1)

     3300    Å  
     

  • Option 2)

     4400    Å   

  • Option 3)

    5500    Å  

     

  • Option 4)

     6600 Å

 

Answers (1)

As we have learned

Fraunhofer Diffraction -

b\sin \theta = n\lambda
 

- wherein

Condition of nth minima.

b= slit width

\theta = angle of deviation

 

 For first maxima 

b \sin \theta = \frac{3\lambda }{2}........(1)

For first  minima of red light 

b \sin \theta = \lambda _{red}

\Rightarrow \lambda _{red}= \frac{3\lambda }{2} \\

or \lambda = \frac{2 \lambda }{3}Red = 4400A \degree

 

 

 


Option 1)

 3300    Å  
 

Option 2)

 4400    Å   

Option 3)

5500    Å  

 

Option 4)

 6600 Å

Posted by

Vakul

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