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  • Answer please! Rain is falling vertically with a speed of 35 m/s. Wind start blowing after some time with a speed of 12 m/s in east to west direction. In which direction should a boy waiting at a bus stop hold his umbrella with the vertical?

Rain is falling vertically with a speed of 35 m/s. Wind start blowing after some time with a speed of 12 m/s in east to west direction. In which direction should a boy waiting at a bus stop hold his umbrella with the vertical?

  • Option 1)

    \sin^{-1}\left(\frac{12}{35} \right )

  • Option 2)

    \cos^{-1}\left(\frac{12}{35} \right )

  • Option 3)

    \tan^{-1}\left(\frac{12}{35} \right )

  • Option 4)

    \cot^{-1}\left(\frac{12}{35} \right )

 

Answers (1)

As we have learnt,

 

Rain - Man Problem -

tan\Theta = \frac{V_{r}}{V_{m}}\\*

\Theta = angle which relative velocity of rain with

            respect to man make with the vertical


 

- wherein

\overrightarrow{V_{r}}= velocity of rain falling vertically

\overrightarrow{V_{m}}= velocity of man in horizontal direction

 

  

\tan\theta = \frac{V_w}{V_r} = \frac{12}{35} \therefore \theta = \tan^{-1}\frac{12}{35}


Option 1)

\sin^{-1}\left(\frac{12}{35} \right )

Option 2)

\cos^{-1}\left(\frac{12}{35} \right )

Option 3)

\tan^{-1}\left(\frac{12}{35} \right )

Option 4)

\cot^{-1}\left(\frac{12}{35} \right )

Posted by

subam

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