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 Water is flowing at a speed of 1.5 ms-1 through a horizontal tube of cross-sectional area 10-2 m2 and you are trying to stop the flow by your palm. Assuming that the water stops immediately after hitting the palm, the minimum force that you must exert should be (density of water=103 kgm-3).

 

  • Option 1)

    15 N

  • Option 2)

    22.5 N

  • Option 3)

    33.7

  • Option 4)

    45 N

 

Answers (1)

best_answer

As we have learned

Equation of Continuity -

Mass of the liquid entering per second at A = mass of the liquid leaving per second at B. 

a1 v1 = a2 v2 

- wherein

a1  and abe the area of cross section.

Let us say speed of water is v and area of cross section is A 

In one second mass of water that flows is m = \rho A v

F = momentum change per second 

mv = \rho A v ^2= 10 ^3 \times 10^{-2}\times (1.5 )^2= 22.5 N

 

 

 

 

 


Option 1)

15 N

Option 2)

22.5 N

Option 3)

33.7

Option 4)

45 N

Posted by

SudhirSol

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