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As shown in arrangement waves with identical wavelengths and amplitudes and that are initially in phase travel through different media, Ray 1 travels through air and Ray 2 through a transparent medium for equal length L, in four different situations. In each situation the two rays reach a common point on the screen. The number of wavelengths in length L is N2 for Ray 2 and Nfor Ray 1. In the following table, values of N1 and N2 are given for all four situations, The order of the situations according to the intensity of the light at the common point in descending order is :

Option: 1

I_{3}=I_{4}>I_{2}>I_{1}


Option: 2

I_{1}>I_{3}>I_{4}>I_{2}


Option: 3

I_{1}>I_{2}>I_{3}>I_{4}


Option: 4

I_{2}>I_{3}=I_{4}>I_{1}


Answers (1)

best_answer

In cases I, II, III, IV the path differences are respectively  \frac{\lambda }{2},\lambda,\frac{\lambda }{4}\;\; and \;\;\frac{3\lambda }{4}

\Rightarrow phase differences are respectively   \pi,2\pi,\pi/2,3\pi/2

and intensity is given as  - I= I_{max}\cdot \cos ^{2}\frac{\phi}{2}

\thereforethe intensity in the four cases are   0,I_{max},\frac{I_{max}}{2},\frac{I_{max}}{2} respectively

 

Posted by

vishal kumar

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