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As shown in the figure block of mass m is placed on a smooth inclined plane which is accelerating with speed b. What should be the value of 'b' so that the block m remains stationary w.r.t. incline plane is:

Option: 1

\frac{2}{\sqrt{3}}g
 


Option: 2

\frac{\sqrt{3}}{2}g


Option: 3

\sqrt{3g}

 


Option: 4

\frac{g}{\sqrt{3}}


Answers (1)

best_answer

Acceleration of Block on Smooth Inclined Plane -

When an Inclined Plane is given Acceleration 'b'

R=mg \:cos\theta +mb\:sin\theta

ma= mg\:sin\theta -mb\:cos\theta

a=g\:sin\theta -b\:cos\theta

\ast  Condition for the body to be at rest relative to the inclined plane.

a=g\:sin\theta -b\:cos\theta =0

b=g\:tan\theta

-

On the basis of this,

for the block to be stationary

Posted by

Sayak

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