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  • Assume that a lamp radiates power  uniformly in all directions. What is the magnitude of electric

Assume that a lamp radiates power \mathrm{P} uniformly in all directions. What is the magnitude of electric field strength at a distance  \mathrm{r} from the lamp?

Option: 1

\frac{P}{\pi c \varepsilon_0 r^2}


Option: 2

\frac{P}{2 \pi c \varepsilon r^2}


Option: 3

\sqrt{\frac{P}{2 \pi \varepsilon_0 r^2 c}}


Option: 4

\sqrt{\frac{P}{\pi \varepsilon_0 c r^2}}


Answers (1)

best_answer

The frequency of Electromagnetic Waves produced by the oscillator is equal to the frequency of the oscillating particle  
\mathrm{\begin{aligned} & \text { Intensity } I=\frac{\text { pressure }}{\text { area }}=\frac{p}{4 \pi r^2} \\ & =\text { average energy density } \times \text { velocity } \\ & =\frac{1}{2} \varepsilon_0 E_0^2 c \\ & \therefore E_0=\sqrt{\frac{2 P}{4 \pi \varepsilon_0 r^2 c}}=\sqrt{\frac{P}{2 \pi \varepsilon_0 r^2 c}} \end{aligned}}

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avinash.dongre

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