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  • Assuming human pupil to have a radius of 0.25 cm and a comfortable viewing distance of 25 cm, the minimum separation between two objects that human eye can resolve at 500 nm wavelength is :

Assuming human pupil to have a radius of 0.25 cm and a comfortable viewing distance of 25 cm, the minimum separation between two objects that human eye can resolve at 500 nm wavelength is :

 

Option: 1

1\mu m


Option: 2

30\mu m


Option: 3

100 \mu m


Option: 4

300 \mu m


Answers (1)

best_answer

Radius of human solution pupil=0.25cm or diameter =0.5cm=5x10-3m

\lambda =500mm=5\times 10^{-7}m

Since \sin \theta =\frac{1.22\lambda }{d}=\frac{1.22\times 5\times 10^{-7}}{5\times 10^{-3}}=1.22\times 10^{-4}

The distance of comfortable viewing =25cm 

Let x be the minimum separation between the two object that the human eye can resolve them

\sin \theta =\tan \theta =\frac{x}{0}\:or\:0\tan \theta =x x=(25cm)\times 1.22\times 10^{-4}\\ =3\times 10^{-5}m=30\mu m

Posted by

Ajit Kumar Dubey

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