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  • Atomic weight of boron is 10.81 and it has two isotopes and <img alt="\mathrm{{ }_5 B^{11}}" src="/

Atomic weight of boron is 10.81 and it has two isotopes \mathrm{{ }_5 B^{10}} and \mathrm{{ }_5 B^{11}}. Then ratio of \mathrm{{ }_5 B^{10}:_5 B^{11}} in nature would be

Option: 1

19 : 81


Option: 2

10 : 11


Option: 3

15 : 16


Option: 4

81 : 19


Answers (1)

best_answer

Let the percentage of \mathrm{B^{10}} atoms be \mathrm{x}, then Average atomic weight

\mathrm{=\frac{10 x+11(100-x)}{100}=10.81 \Rightarrow x=19 \quad \therefore \frac{N_{B^{10}}}{N_{B^{11}}}=\frac{19}{81}}

Posted by

Ritika Harsh

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