Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Can someone explain A conducting sphere of radius R, and carrying a charge q is joined to a conducting sphere of radius 2R, and carrying a charge – 2q. The charge flowing between them will be

A conducting sphere of radius R, and carrying a charge q is joined to a conducting sphere of radius 2R, and carrying a charge – 2q. The charge flowing between them will be

  • Option 1)

    \frac{q}{3}


     

  • Option 2)

    \frac{2q}{3}

  • Option 3)

    q

  • Option 4)

    \frac{4q}{3}

 

Answers (1)

best_answer

As we learned

 

At the surface of Sphere -

V=R

E_{s}=\frac{1}{4\pi \epsilon _{0}}\frac{Q}{R^{2}}=\frac{\sigma }{\epsilon _{0}}

V_{s}=\frac{1}{4\pi \epsilon _{0}}\frac{Q}{R}=\frac{\sigma R}{\epsilon _{0}}

-

 

 Initial charge on sphere of radius R = q

Charge on this sphere after joining {q}'=\frac{(q+(-2q)\times R)}{R+2R}=\frac{-q\times R}{3R}=-\frac{q}{3}

Now charge flowing between them =q-\left ( -\frac{q}{3} \right )=\frac{4q}{3}

 


Option 1)

\frac{q}{3}


 

Option 2)

\frac{2q}{3}

Option 3)

q

Option 4)

\frac{4q}{3}

Posted by

Aadil

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main Result 2024 Live: JEE Mains session 2 results at jeemain.nta.ac.in soon; rank predictor
anam-khan

JEE Main 2024 session 2 final answer key out at jeemain.nta.ac.in; steps to check probable scores
anam-khan

JEE Main Result 2024 Live: Download session 2 final answer key at jeemain.nta.ac.in; rank predictor, cutoff

Latest Question