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  • Can someone explain - Sets, Relations and Functions - JEE Main-6

If f(x)= x^2+2; then find g(x) such that it is the inverse of f(x)  

  • Option 1)

    \sqrt{x-2}, x \geq 0

  • Option 2)

    \sqrt {x-2}; x\geq 2

  • Option 3)

    \sqrt{x-2}; x\geq 3

  • Option 4)

    \sqrt {x-2}; x\geq 1

 

Answers (1)

best_answer

As we have learned

Property of Inverse -

The inverse of a bijection is also a bijection.

-

 

 y= x^2+2

x^2=y-2

x=\sqrt{y-2}

so inverse g(x)=\sqrt{x-2}; x\geq 2

Because g(x) is only defined when x\geq 2

 


Option 1)

\sqrt{x-2}, x \geq 0

Option 2)

\sqrt {x-2}; x\geq 2

Option 3)

\sqrt{x-2}; x\geq 3

Option 4)

\sqrt {x-2}; x\geq 1

Posted by

Himanshu

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