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The equation of obtuse bisetor plane of 3x-2y-6z+1=0 and 2x-3y+6z-2=0 is

  • Option 1)

    5x-5y-1=0

  • Option 2)

    x+y+12z+3=0

  • Option 3)

    x-y+12z-3=0

  • Option 4)

    5x+5y+1=0

 

Answers (1)

best_answer

As we have learned

Bisector of obtuse and acute angle between two planes -

Let the planes be

ax+by+cz+d= 0 and 

a_{1}x+b_{1}y+c_{1}z+d_{1}= 0

Where  d \: and\: d_{1}  are positive

If  a_{1}a+b_{1}b+c_{1}c > 0 , then the angle bisector with + sign is obtuse angle bisector and angle bisector with – sign is acute angle bisector.

If  a_{1}a+b_{1}b+c_{1}c < 0  ,then the angle bisector with – sign is obtuse angle bisector and angle bisector with + sign is acute angle bisector.

-

 

 Planes can be written as 3x-2y-6z+1=0 and -2x+3y-6z+2=0, Now 3(-2)+(-2)3+(-6)(-6)=24>0

so obtuse bisector will be given by  x+y-12z+3=0


Option 1)

5x-5y-1=0

Option 2)

x+y+12z+3=0

Option 3)

x-y+12z-3=0

Option 4)

5x+5y+1=0

Posted by

Himanshu

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