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 For LED’s to emit light in visible region of electromagnetic light, it should have energy band gap in the range of :   

 

  • Option 1)

      0.1 eV to 0.4 eV  
     

     

  • Option 2)

    0.5 eV to 0.8 eV  
     

  • Option 3)

     0.9 eV to 1.6 eV  
     

  • Option 4)

    1.7 eV to 3.0 eV  

 

Answers (1)

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As we have learned

Photo diode -

A special type of photo detector.

- wherein

By measuring the change in the conductance of the semicondutors one can measure the intensity of the optical signal

 

 For emitting visible light \lambda  should lie between 34000 A \degree to 7600 A \degree 

\therefore E ^{min }= \frac{12400}{7600}= 1.7 eV

\therefore E ^{max }= \frac{12400}{4000}= 3.1 eV

 

 

 

 


Option 1)

  0.1 eV to 0.4 eV  
 

 

Option 2)

0.5 eV to 0.8 eV  
 

Option 3)

 0.9 eV to 1.6 eV  
 

Option 4)

1.7 eV to 3.0 eV  

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