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  • Can someone help me with this, - Redox Reaction and Electrochemistry - JEE Main-2

The correct order of the oxidation states of nitrogen in NO,N_{2}O,NO_{2} and N_{2}O_{3} is :

  • Option 1)

     NO_{2}< NO< N_{2}O_{3}< N_{2}O

  • Option 2)

     NO_{2}< N_{2}O_{3}< NO< N_{2}O

     

     

  • Option 3)

     N_{2}O< N_{2}O_{3}< NO< NO_{2}

  • Option 4)

    N_{2}O<NO< N_{2}O_{3}< NO_{2}

Answers (2)

best_answer

The oxidation state of Nitrogen in 

NO\rightarrow +2\; \; \Rightarrow N+\left ( -2 \right )=0\Rightarrow N=+2

N_{2}O\rightarrow +1\; \; \Rightarrow2 N-2 =0\Rightarrow N=+1

NO_{2}\rightarrow +4\; \; \Rightarrow N-2 \times 2=0\Rightarrow N=+4

N_{2}O_{3}\rightarrow +3\; \; \Rightarrow 2N - 2\times 3=0\Rightarrow N=+3

Order would be

N_{2}O< NO< N_{2}O_{3}< NO_{2}


Option 1)

 NO_{2}< NO< N_{2}O_{3}< N_{2}O

Option 2)

 NO_{2}< N_{2}O_{3}< NO< N_{2}O

 

 

Option 3)

 N_{2}O< N_{2}O_{3}< NO< NO_{2}

Option 4)

N_{2}O<NO< N_{2}O_{3}< NO_{2}
Posted by

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Option 4

 

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