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  • Can someone help me with this, Three electrolytic cells A, B, C containing solution of ZnSO4, AgNO3and CuSO4repectively are connected in seris. A steady current of 1.5 Amepere was passed through them until 1.45g of silver is deposited at the cathode

Three electrolytic cells A, B, C containing solution of ZnSO4 , AgNO3 and CuSO4 repectively are connected in seris. A steady current of 1.5 Amepere was passed through them until 1.45g of silver is deposited at the cathode of all B. How long did the current flew?

  • Option 1)

    13.4 min

  • Option 2)

    14.4 min

  • Option 3)

    15.4 min

  • Option 4)

    16.4 min

 

Answers (1)

best_answer

As we have learnt,

 

Second law of electrolysis -

The masses of different substances, liberated or dissolved by the electricity are proportional to their equivalent masses.

-

 

 

Ag^+ + e^- \rightarrow Ag \;\;\; E_{Ag} = \frac{108}{1} \\* Eq. of Zn = Eq of Cu = Eq of Ag = \frac{i\cdot t}{96500} = \frac{1.45}{108} = \frac{1.5\times t}{96500} \\*\Rightarrow t = 864 sec = 14.4 min


Option 1)

13.4 min

Option 2)

14.4 min

Option 3)

15.4 min

Option 4)

16.4 min

Posted by

satyajeet

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