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  • Can someone help me with this, When 100 g of a liquid A at 100oC is added to 50 g of a liquid B at temperature 75oC , the temeprature of the mixture becomes 90oC. The temperature of the mixture, if 100 g of liquid A at 100oC is added to 50 g of liquid B a

When 100 g of a liquid A at 100oC is added to 50 g of  a liquid B at temperature 75oC , the temeprature of the mixture becomes 90oC. The temperature of the mixture, if 100 g of liquid A at 100oC is added to 50 g of liquid B at 50oC, will be :

  • Option 1)

    85oC

  • Option 2)

    60oC

  • Option 3)

    80oC

  • Option 4)

    70oC

Answers (1)

best_answer

 

Specific Heat -

C=\frac{Q}{m.\Delta \theta}

- wherein

C = specific heat

\Delta \theta=Change in temperature 

m = Amount of mass

 

For (I) 

100\times S_{A}\times \left ( 100-90 \right )=50\times S_{B}\times \left ( 90-75 \right )

S_{A}=\frac{1.5}{2}S_{B}=\frac{3}{4}S_{B}\cdots \left ( 1 \right )

now for (II)

100\times S_{A}\times \left ( 100-T \right )=50\times S_{B}\times \left ( T-50 \right )

\Rightarrow 2S_{A}\left ( 100-T \right )=S_{B}\left ( T-50 \right )\cdots \left ( 2 \right )

From (1) & (2)

2\times \frac{3}{4}\times \left ( 100-T \right )=\left ( T-50 \right )

3\left ( 100-T \right )=2\left ( T-50 \right )

300-3T=2T-100

400=5T

T=80^{\circ}C

 

 

 


Option 1)

85oC

Option 2)

60oC

Option 3)

80oC

Option 4)

70oC

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