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Which of the functions are not equal ?

  • Option 1)

    f(x)=\left ( x+1 \right )^{2}\, ;\, g(x)=x^{2}+2x+1

     

     

     

  • Option 2)

    f(x)=x\, ;\, g(x)=\frac{x^{2}}{x}

  • Option 3)

    f(x)=\left ( x-2 \right )^{2}\, ;\, g(x)=x^{2}-4x+4

  • Option 4)

    All of the above are equal.

 

Answers (1)

best_answer

As we learned 

 

Equality of function -

The two function f and g are said to be equal

iff :     dom (f) = dom (g)

and     Co-dom (f) =Co - dom (g)      

and    f(x) = g (x)         x \in Domain

-

 

 g(x)=\frac{x^{2}}{x} is not defined for x=0.

while f(x)=x\: \: \forall x\equiv R.

 


Option 1)

f(x)=\left ( x+1 \right )^{2}\, ;\, g(x)=x^{2}+2x+1

 

 

 

Option 2)

f(x)=x\, ;\, g(x)=\frac{x^{2}}{x}

Option 3)

f(x)=\left ( x-2 \right )^{2}\, ;\, g(x)=x^{2}-4x+4

Option 4)

All of the above are equal.

Posted by

Himanshu

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