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  • Confused! kindly explain, - Electrostatics - JEE Main-11

An \alpha-particle is accelerated through a potential difference of 200V. The increase in its kinetic energy is 

  • Option 1)

    100eV

  • Option 2)

    200eV

  • Option 3)

    400eV

  • Option 4)

    800eV

 

Answers (1)

best_answer

As we have learnt,

 

Electron Volt -

It is the smallest practical unit of energy if used in atomic and nuclear Physics.

 

 

 

- wherein

1\, e v= 1.6\times 10^{-19}J

1.6\times 10^{-12}erg.

 

 KE = QV = (2e)200V = 400eV

 


Option 1)

100eV

Option 2)

200eV

Option 3)

400eV

Option 4)

800eV

Posted by

Avinash

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